The formula is radium plus water.

Explanation of the solution to the problem: only metals of medium activity or active metals can interact with water.
If an active metal enters the reaction, then as a result of the reaction, a hydroxide of this metal and a hydrogen molecule are formed, and if a metal of medium activity reacts, then an oxide of this metal and hydrogen are formed.
Answer: radium is a very active metal, therefore, as a result, radium hydroxide will be obtained, since radium is in group II, its valence is 2. We compose the reaction equation:
Ra + 2H2O => Ra (OH) 2 + H2.



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