The free fall of the body lasted 6s. At what height was the body 2 seconds before falling to the ground?

Since the body began to fall without an initial velocity, then
h = (g * t ^ 2) / 2, where h is the height from which the body fell (m), g is the acceleration of gravity (we take g = 10 m / s ^ 2), t is the time of the body falling (t = 6 s).
h = (g * t ^ 2) / 2 = (10 * 6 ^ 2) / 2 = 10 * 36/2 = 180 m.
2 s before the fall, the body passed the distance:
h1 = (g * t1 ^ 2) / 2 = (10 * 4 ^ 2) / 2 = 10 * 16/2 = 80 m.
The height at which the body was located 2 s before the fall:
h2 = h – h1 = 180 – 80 = 100 m.
Answer: The body was at an altitude of 100 m.