The free falling body has passed the last 30 m in 0.5 s. Find the drop height.

Data: h1 (the last leg before the fall) = 30 m; t1 (considered fall time) = 0.5 s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Total duration of the fall: S = h – h1 = g * t ^ 2/2 – g * (t – t1) ^ 2/2 = 10 * t ^ 2/2 – 10 * (t – 0.5) ^ 2/2 = 5 * t ^ 2 – 5t ^ 2 + 5t – 1.25 = 5t – 1.25 = 30, whence t = (30 + 1.25) / 5 = 6.25 s.

2) Fall height: H = g * t ^ 2/2 = 10 * 6.25 ^ 2/2 = 195.3125 m.

Answer: The height of the fall is 195.3125 m.