The freeform body was placed in a beaker filled with water, and the water level

The freeform body was placed in a beaker filled with water, and the water level rose from 100 to 150 cm3. Calculate the buoyancy force acting on a body in water

Some body was placed in water. The water level in the beaker has changed by 150 cm3 – 100 cm3 = 50 cm3. It is necessary to calculate the force of Archimedes acting on the body.

First, let’s convert the units of measurement to the SI system:

50 cm3 = 0.00005 m3

Archimedes’ force is calculated by the formula:

F arch. = ρ × g × V

The density of water is a tabular value equal to 1000 kg / m3.

The gravitational constant is 10 N / kg.

Substitute the numbers into the formula and find the answer:

F arch. = 1000 kg / m3 × 10 N / kg × 0.00005 m3

F arch. = 0.5 N

Let’s write down the answer:

Answer: F arch. = 0.5 N



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