The frequency of electrical oscillations in the circuit is 1.5 MHz. Determine the inductance of the coil

The frequency of electrical oscillations in the circuit is 1.5 MHz. Determine the inductance of the coil if the capacitance of the capacitor is 300pF.

Initial data: ν (frequency of electrical oscillations in the circuit) = 1.5 MHz; C (capacitor value) = 300 pF.

SI system: ν = 1.5 MHz = 1.5 * 10 ^ 6 Hz; C = 300 pF = 300 * 10 ^ -12 F.

1) Determine the period of electrical oscillations in the circuit: T = 1 / ν = 1 / (1.5 * 10 ^ 6) = 0.667 * 10 ^ -6 s.

2) Let us express from the Thompson formula and calculate the inductance of the coil: T = 2 * Π * √ (L * C); √ (L * C) = T / 2Π; L * C = (T / 2Π) ^ 2; L = (T / 2Π) ^ 2 / C = (0.667 * 10 ^ -6 / (2 * 3.14)) ^ 2 / (300 * 10 ^ -12) = 3.76 * 10 ^ -5 H.