The frequency of electrical oscillations in the circuit is 2 MHz. Determine the capacitance of the capacitor
| February 26, 2021 | education
The frequency of electrical oscillations in the circuit is 2 MHz. Determine the capacitance of the capacitor if the inductance is 250 μH.
To determine the value of the capacitance of the capacitor used in the circuit, apply the Thomson formula: ν = 1 / T = 1 / (2 * Π * √ (C * L)) and C = 1 / (ν ^ 2 * 4 * Π ^ 2 * L) …
Values of variables: ν – frequency of electrical oscillations (ν = 2 MHz = 2 * 10 ^ 6 Hz); L – loop inductance (L = 250 μH = 250 * 10 ^ -6 H).
Calculation: С = 1 / (ν ^ 2 * 4 * Π ^ 2 * L) = 1 / ((2 * 10 ^ 6) ^ 2 * 4 * 3.142 * 250 * 10 ^ -6) = 2.54 * 10 ^ -11 F = 25.4 pF.
Answer: The capacitor used in the circuit has a capacitance of 25.4 pF.
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