The frequency of electromagnetic oscillations in the circuit is 500 kHz. What is the electrical capacity

The frequency of electromagnetic oscillations in the circuit is 500 kHz. What is the electrical capacity of this circuit if the inductance is 1 mH?

These tasks: ν (frequency of electromagnetic oscillations) = 500 kHz = 5 * 10 ^ 5 Hz; L (loop inductance) = 1 mH = 10 ^ -3 H.
The electrical capacity of the presented circuit can be determined using the Thomson formula: T = 1 / ν = 2 * Π * √ (C * L) and C = 1 / (ν ^ 2 * 4 * Π ^ 2 * L).
Let’s make a calculation: С = 1 / (ν ^ 2 * 4 * Π ^ 2 * L) = 1 / ((5 * 105) ^ 2 * 4 * 3.14 ^ 2 * 10 ^ -3) = 1 * 10 ^ -10 F = 100 pF.
Answer: The electrical capacity of the presented circuit is 100 pF.