The gas is heated isochorically by 100 K. The internal energy has changed in this case by 100 J.

The gas is heated isochorically by 100 K. The internal energy has changed in this case by 100 J. Determine the amount of heat transferred to the gas, work and change in the internal energy of the gas.

ΔТ = 100 K.
ΔU = 100 J.
V = const.
Q -?
A -?
Isochoric is a process in which the volume of gas does not change V = const.
According to the first law of thermodynamics: the amount of heat Q, which is transferred to the gas, goes to change its internal energy ΔU and to perform work A.
Q = ΔU + A.
Since the volume of the gas does not change, it means that the gas does not perform work A = 0.
This means that all the transferred heat energy is used to increase the internal energy of the gas Q = ΔU.
The gas was transferred to Q = 100 J of thermal energy.
Answer: Q = 100 J of thermal energy was transferred to the gas, the internal energy of the gas increased by ΔU = 100 J, the gas did not perform work A = 0.