The gas is under pressure p = 20 * 10 ^ 4 Pa at a temperature of 290 K. What is the average kinetic energy
| December 19, 2020 | education
The gas is under pressure p = 20 * 10 ^ 4 Pa at a temperature of 290 K. What is the average kinetic energy of the translational motion of one molecule?
Given:
T = 290k
K = 1.38 * 10 ^ -23J / K * mol (Boltzmann constant)
Ek-?
Decision:
Ek = 3 / 2KT = 3/2 * 1.38 * 10 ^ -23 * 290≈6 * 10 ^ -22 (J)
Answer: Ek = 6 * 10 ^ 22 J
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