The gas obtained as a result of the thermal decomposition of 61.25 g of potassium chlorite was detonated with the gas

The gas obtained as a result of the thermal decomposition of 61.25 g of potassium chlorite was detonated with the gas that was obtained by placing 23 g of sodium in water. Determine the mass of the compound resulting from the explosion.

1) Potassium Chlorite – KClO3

Oxygen is released during the decomposition of potassium chlorite. Let us write down the reaction equation for the decomposition of chlorite and calculate the amount of the substance of the released oxygen:

2 KClO3 = 2 KCl + 3 О2

M (KClO3) = 39 + 35.5 + 3 * 16 = 122.5 g / mol

From the reaction equation: 2 * 122.5 g (KClO3) forms 3 mol (O2)

According to the condition of the problem: 61.25 g (KClO3) forms x mol (O2)

X = 61.25g * 3/2 * 122.5g

X = 0.75 mol (O2)

2) When sodium interacts with water, a gas is released – hydrogen.

Let’s write the equation of the reaction of interaction of sodium with water:

2 Na + 2 H2O = 2 NaOH + H2

Calculate the amount of substance released hydrogen: M (Na) = 23 g / mol

From the reaction equation: 2 * 23 g (Na) forms 1 mol (H2)

According to the condition of the problem: 23 g (Na) forms x mol (H2)

X = 23g * 1/2 * 23g

X = 0.5 mol (H2)

3) Consequently: the oxygen formed in the first reaction and exploded with the hydrogen released in the second reaction.

Let’s write down the reaction equation and calculate the mass of the resulting water:

2 H2 + O2 = 2 H2O

2 mol 1 mol 2 mol

0.5 mol 0.75 mol

The calculation will be made for hydrogen, which is in short supply.

M (H2O) = 18 g / mol

X = 0.5 * 2 * 18/2

X = 9 g (H2O)

Answer: 9 g (H2O)