The gas, occupying a volume of 6.6 liters, expands at a constant pressure of 515 kPa

The gas, occupying a volume of 6.6 liters, expands at a constant pressure of 515 kPa to a volume of 33 liters. What kind of work is done with gas?

The work done by the gas can be calculated using the formula:
A = P (V2 – V1), where P is the constant gas pressure (P = 515 kPa = 515 * 10 ^ 3 Pa), V2 is the final volume of gas (V2 = 33 l = 33 dm ^ 3 = 33 * 10 ^ – 3 m ^ 3), V1 is the initial gas volume (V1 = 6.6 l = 6.6 dm ^ 3 = 6.6 * 10 ^ -3 m ^ 3).
Let’s calculate the work of gas:
A = P (V2 – V1) = (515 * 10 ^ 3) * (33 * 10 ^ -3 – 6.6 * 10 ^ -3) = (515 * 10 ^ 3) * (26.4 * 10 ^ -3) = 13596 J ≈ 13.6 kJ.
Answer: Work equal to 13.6 kJ is performed with gas.