The gas received 209.5 kJ of heat from the heater. How much heat did the gas give to the refrigerator if the cycle efficiency is 0.4?
| January 4, 2021 | education
Given:
n = 0.4
Qн = 209.5 kJ = 209500 J
Find: Qx =?
Decision:
n = 1 – (Qx / Qn)
1-n = Qx / Qн
Qx = Qн * (1-n)
Qx = 209500 J * (1-0.4)
Qx = 209500J * 0.6
Qx = 125700 J
Answer: Qx = 125700 J
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