The gas was transferred to 20 kJ of heat, what is the change in internal energy
| January 28, 2021 | education
The gas was transferred to 20 kJ of heat, what is the change in internal energy, if it did work equal to 60 kJ. Was the gas cooled or heated?
A = 60 kJ = 60,000 J.
Q = 20 kJ = 20,000 J.
ΔU -?
According to the first law of thermodynamics, the amount of heat Q received by the thermodynamic system is spent on: performing mechanical work A by this system or changing its internal energy: Q = A + ΔU.
ΔU = Q – A.
ΔU = 60,000 J – 20,000 J = 40,000 J.
ΔU = U2 – U1 = 40,000 J.
The internal energy of the gas has increased, since U2> U1, which means it has heated up.
Answer: the gas has heated up, and its internal energy has increased by ΔU = 20,000 J.
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