The general formula for the first half of the journey the bus traveled at a speed of 3 times more than the second

| August 2, 2021 | education

The general formula for the first half of the journey the bus traveled at a speed of 3 times more than the second average speed along the entire route is 36 km / h. Determine the speed of the bus on the second half of the journey.

Data: S1 (length of the first leg) = 0.5S = S2 (length of the second leg); V1 (speed in the first section) = 3V2 (speed in the second section); Vav. (the average speed of this bus along the entire route) = 36 km / h.

We express the speed of this bus on the second half of the journey from the formula: Vav. = S / (t1 + t2) = S / (S1 / V1 + S2 / V2) = S / (0.5S / 3V2 + 0.5S / V2) = 1 / (1 / 6V2 + 1 / 2V2) = 1 / (2 / 3V2) = 1.5V2 = 36.

V2 = 36 / 1.5 = 24 km / h.

Answer: The speed on the second half of the journey was 24 km / h.



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