The generatrix of the cone is inclined to the plane of the base at an angle of 30 degrees, the radius

The generatrix of the cone is inclined to the plane of the base at an angle of 30 degrees, the radius of the base is 3 dm. Find the volume of the cone and its area to the lateral surface.

From the right-angled triangle ABO, we determine the length of the OB leg and the hypotenuse AB.

tgBAO = BO / AO.

BO = AO * tg30 = 3 * √3 / 3 = √3 dm.

Then, by the Pythagorean theorem, AB ^ 2 = AO ^ 2 + BO ^ 2 = 9 + 3 = 12.

AB = 2 * √3 dm.

Determine the area of the base of the cone.

Sb = π * R2 = 9 * π cm2.

Then V = Sosn * BО / 3 = 9 * π * √3 / 3 = 3 * √3 * π dm3.

Let us determine the area of the lateral surface of the cone.

Side = π * R * AO = π * 3 * 2 * √3 = 6 * √3 * π cm2.

Answer: The volume of the cone is 3 * √3 * π dm3, the lateral surface area is 6 * √3 * π cm2.



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