The given alloy contains 30% tin and another 70% tin, how many kg is needed to get 100 kg from 46%

univerkov | September 8, 2021 | education

Let’s take the amount of 30% alloy for x, for y – 70%. Then:

0.3 * x – the amount of pure tin in the 1st alloy;

0.7 * y – in the 2nd.

We get the equation:

0.3x + 0.7y = 100 * 46/100

0.3x + 0.7y = 46.

There is not enough data on the amount of the 1st alloy to solve.

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