The graph of the equation 8x-5y = 14 passes through a point with abscissa 1,2. Find the ordinate of this point

The condition says that the graph of the equation 8x – 5y = 14 passes through a point with an abscissa equal to 1.2. In order to find the ordinate of this point, we substitute it into the equation x = 1.2 and solve the resulting linear equation.

So, we substitute x = 1.2 and get:

8 * 1.2 – 5y = 14;

9.6 – 5y = 14;

We group the terms with and without variables in different parts of the equation. When transferring terms from one side of the equation to another, we change the sign of the term to the opposite.

-5y = 14 – 9.6;

-5y = 4.4;

y = 4.4: (-5):

y = -0.88.