The gun is installed at an angle of 30 ° to the horizon. The projectile departure speed is 1200 m / s

The gun is installed at an angle of 30 ° to the horizon. The projectile departure speed is 1200 m / s. Determine the horizontal component of this speed.

Given:

V = 1200 meters per second – the velocity of the projectile departure from the gun barrel;

a = 30 degrees – the angle of inclination of the gun to the horizon.

It is required to determine Vhorizontal (meter per second) – the horizontal component of the velocity.

Let us introduce a coordinate system with axes directed along the horizon (X-axis) and vertically up (Y-axis), then the horizontal component of the velocity will be equal to:

V horizontal = V * sin (a) = 1200 * sin (30) = 1200 * 0.5 = 600 meters per second.

Answer: the horizontal component of the speed is 600 meters per second.