The half-life of radioactive copper is 10 minutes. What fraction of the initial amount of copper will remain after 0.5 h?

Given: the half-life of radioactive copper is 10 minutes. Find the fraction of the initial amount of copper that will remain after 0.5 h?

Since the half-life implies that the amount of the substance will be halved. Then

After 10 minutes of the half-life of radioactive copper, half will remain.

After 20 minutes of the half-life of radioactive copper, a quarter will remain.

After 30 minutes of the half-life of radioactive copper, an eighth will remain.

That is, after 0.5 hours or 30 minutes, 1/8 of copper will remain.



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