The hammer, moving at a speed of 5.0 m / s, strikes a small nail. Hammer weight 0.80 kg.

The hammer, moving at a speed of 5.0 m / s, strikes a small nail. Hammer weight 0.80 kg. What is the average impact force if its duration is 0.10 s?

Task data: V (speed of the hammer) = 5 m / s; m (hammer weight) = 0.8 kg; t (duration of impact on a small nail) = 0.1 s.

We express the average force of a hammer blow on a small nail from the equality: m * V = F * t, whence F = m * V / t.

Let’s make a calculation: F = 0.8 * 5 / 0.1 = 40 N.

Answer: The hammer hit a small nail with an average impact force of 40 N.