The hare hits the lion with a force of 20N. With what force does the lion act on the hare when it hits?

According to Newton’s 3 laws: in the interaction of two bodies, the force F12, with which the first body acts on the second, is numerically equal to the force F21, with which the second body acts on the first and directed in opposite directions: F12 = – F21.
Since the lion’s hare hit with a force of F12 = 20 N, the lion hit the hare F21 with the same force F21 = 20 N.



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