The heat capacity of ice is 2100 J / kg in degrees Celsius. How much energy is required to heat 1kg of ice by 2 degrees?

To find the heat expended to heat the taken ice, we will use the formula: Q = Сl * m * Δt.

Constants and variables: Сl – specific heat capacity of ice (according to the condition Сl = 2100 J / (kg * K)); m is the mass of taken ice (m = 1 kg); Δt – change (increase) in temperature (Δt = 2 ºС).

Calculation: Q = Сl * m * Δt = 2100 * 1 * 2 = 4.2 * 10 ^ 3 J = 4.2 kJ.

Answer: To heat the taken ice by 2 ºС, 4.2 kJ of thermal energy is required.