The heat engine performs useful work of 150 kJ, while giving off 250 kJ
| February 4, 2021 | education
The heat engine performs useful work of 150 kJ, while giving off 250 kJ of heat to the environment. Determine the efficiency of the heat engine.
These tasks: Qп (useful work of the heat engine taken) = 150 kJ; Qokr (heat given to the environment by the engine) = 250 kJ.
The efficiency of the heat engine taken can be calculated by the formula: η = Qp / Qs = Qp / (Qp + Qocr).
Let’s calculate: η = 150 / (150 + 250) = 150/400 = 0.375 or 37.5%.
Answer: The taken heat engine has an efficiency of 37.5%.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
