The heat engine receives the amount of heat from the heater during the cycle of operation, equal to 3 kJ
| December 2, 2020 | education
The heat engine receives the amount of heat from the heater during the cycle of operation, equal to 3 kJ and gives the refrigerator 2.4 kJ. Determine the efficiency of the motor.
Qx = 2.4 kJ.
Qн = 3 kJ.
Find efficiency
Efficiency = 1- (Qх / Qн) = 1- (2400J / 3000J) = 1-0.8 = 0.2
Percentage efficiency: 0.2 * 100 = 20%
Answer: engine efficiency – 20%
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