The heating element of the belt has a current of 1.5 A at a voltage of 24 V.

The heating element of the belt has a current of 1.5 A at a voltage of 24 V. The element is made of 0.35 m nichrome wire. What is the diameter of the wire?

I = 1.5 A.
U = 24 V.
ρ = 1.1 * 10 ^ -6 Ohm / m.
l = 0.35 m.
d -?
Wire resistance R is determined by the formula: R = ρ * l / S, where ρ is the specific resistance of the material from which the wire is made, l is the length of the wire, S is the cross-sectional area of the wire.
S = n * d ^ 2/4.
R = 4 * ρ * l / P * d ^ 2.
d = √ (4 * ρ * l / P * R).
We find the resistance of the conductor R from Ohm’s law for a section of the circuit: R = I / U.
d = √ (4 * ρ * l * U / P * I).
d = √ (4 * 1.1 * 10 ^ -6 Ohm / m * 0.35 m * 24 V / 3.14 * 1.5 A) = 2.8 * 10 ^ -3 m.
Answer: the diameter of the nichrome wire is d = 2.8 * 10 ^ -3 m.