The heating temperature of an ideal heat engine is 127C, and that of a refrigerator is 7C.
| February 15, 2021 | education
The heating temperature of an ideal heat engine is 127C, and that of a refrigerator is 7C. What amount of heat is given to the refrigerator in 1 s if the engine receives 50 kJ of energy from the heater every second?
To find the heat given to the engine refrigerator in 1 second, we use the equality: 1 – Qх / Qн = η (engine efficiency) = 1 – Тх / Тн, from where we express: Qх = Тх * Qн / Тн.
Values of variables: Тх – engine cooler temperature (Тх = 7 ºС = 280 К); Qн – heat from the heater (Qн = 50 kJ); Тн – temperature of the engine heater (Тн = 127 ºС = 400 К).
Calculation: Qx = Tx * Qn / Tn = 280 * 50/400 = 35 kJ.
Answer: 35 kJ of heat is given to the refrigerator in 1 second.
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