The heating temperature of an ideal heat engine is 227C and the temperature of the refrigerator is 27C.

The heating temperature of an ideal heat engine is 227C and the temperature of the refrigerator is 27C. What is the efficiency (efficiency) and the amount of heat received by the working fluid from heating, if the amount of heat of the refrigerator is 5kJ.

Let us write down the formula for finding the efficiency of an ideal heat engine, it is equal to the difference between the temperatures of the heater and the refrigerator, divided by the initial temperature of the heater:

η = (T1 – T2) / T1 = (227 OC – 27 OC) / 227 OC = 0.881 = 88.1%.

Let’s write down the 2nd formula for the amount of heat received by the body from the heater:

η = QT / QX ®

QT = ηQX = 0.881 * 5000 J = 4405 J.

Answer: η = 88.1%; QT = 4405 J.