The height AH of rhombus ABCD divides the side of CD into segments DH = 16 and CH = 4. find the height of the rhombus.

The side of the CD rhombus is DH + HC = 16 + 4 = 20; All sides of the rhombus are equal, so AB = 20;

In a right-angled triangle AHD, the sum of the squares of the legs is equal to the hypotenuse, that is,

AB2 = AH^2 + DH^2; 20^2 = AH^2 + 162; AH = √ (400 – 256) = 12;

Answer: The height of the rhombus is 12.



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