The height AK of an acute-angled isosceles triangle ABC (AB = BC) is 12 cm, KB = 9 cm. Find the sides of triangle ABC.

1) From the right-angled triangle ABK, we find the side AB by the Pythagorean theorem
AB = under the root 12 ^ 2 + 9 ^ 2 = 15
2) AB = BC = 15
3) KS = 15-9 = 6
4) From the right-angled triangle AKC we find the side of the AC
AC = under the root 12 ^ 2 + 6 ^ 2 = root of 180 = 6√5



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