The height AM is drawn in an isosceles triangle ABC with the base AC. Find the MAC angle if the angle B = 68 degrees.

The angles АМВ and ∠АМС are right, since the height of the triangle is perpendicular to its opposite side.
In an isosceles triangle, the angles at the base are equal, which means:
∠ВАС = ∠ВСА;
The sum of the angles of a triangle is 180 °, which means:
∠BAC = ∠BCA = (180 – ∠ABС) / 2;
∠BAC = ∠BCA = (180-68) / 2 = 56;
∠MAC = 180 – (∠AMC + ∠BCA);
∠MAC = 180 – (90 + 56) = 34.
Answer: the angle ∠MAC is 34 °.