The height BD of a right-angled triangle ABC = 24cm cuts off from the hypotenuse AC the segment
| May 4, 2021 | education
The height BD of a right-angled triangle ABC = 24cm cuts off from the hypotenuse AC the segment DC = 18, AB-? cos A?
The height BD is drawn from the vertex of the right angle of the triangle ABC to the hypotenuse AC, then the square of its length is equal to the product of the segments into which BD divides AC.
BD ^ 2 = AD * CD.
AD = BD ^ 2 / CD = 576/18 = 32 cm.
In a right-angled triangle ABD, according to the Pythagorean theorem, we determine the length of the leg AB.
AB ^ 2 = AD ^ 2 + BD ^ 2 = 1024 + 576 = 1600.
AB = 40 cm.
CosBAD = AD / AB = 32/40 = 4/5.
Angle BAD = arcos (4/5).
Answer: The length of the side AB is 40 cm, the angle BAD is equal to arcos (4/5).
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
