The height BD of the triangle ABC divides the base of the AC into segments AD = 7cm

The height BD of the triangle ABC divides the base of the AC into segments AD = 7cm, and DC = 9cm, and the angle A = 45 degrees. Find the area of a triangle

The height BD of triangle ABD forms a right-angled triangle ABD in which one of the acute angles is 45, therefore triangle ABD is rectangular and isosceles, BD = AD = 7 cm.

The length of the segment AC = AD + CD = 7 + 9 = 16 cm.

Determine the area of the triangle ABC,

Sас = АС * ВD / 2 = 16 * 7/2 = 56 cm2.

Answer: The area of triangle ABC is 56 cm2.



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