The height BE of the isosceles trapezoid divides the lower base into 2 cm and 6 cm parts

univerkov | September 3, 2021 | education

The height BE of the isosceles trapezoid divides the lower base into 2 cm and 6 cm parts, find the length of the midline of the trapezoid.

Let’s draw an additional CE height. Triangles ABH and CDE are equal in hypotenuse and acute angle, then DE = AH = 2 cm.

AD = AH + DH = 2 + 6 = 8 cm.

HE = AD – AH – DE = 8 – 2 – 2 = 4 cm.

Quadrangle BCEN is a rectangle, then BC = HE = 4 cm.

KM = (BC + AD) / 2 = (8 + 4) / 2 = 6 cm.

Answer: The length of the middle line is 6 cm.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.