The height BM, drawn from the vertex of the corner of the rhombus ABCD, forms an angle of 30 degrees with side AB

The height BM, drawn from the vertex of the corner of the rhombus ABCD, forms an angle of 30 degrees with side AB, AM = 4 cm. K find the length of the diagonal BD of the rhombus if point M lies on side AD.

If am lies opposite a corner of 30 degrees
Therefore, it is equal to half of the hypotenuse ab: ab = 2am * 4 * 2 = 8, since ab = ad by the rhombus property.
So the answer is: 8



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