The height BM, drawn from the vertex of the corner of the rhombus ABCD, forms an angle of 30 °
The height BM, drawn from the vertex of the corner of the rhombus ABCD, forms an angle of 30 ° with the side AB, AM = 4 cm. Find the length of the diagonal of the rhombus BD if the point M lies on the side AD.
1. In a right-angled triangle ABM, the AM leg is opposite an angle of 30 °.
Therefore, its length, according to the properties of a right-angled triangle, is half the hypotenuse. The hypotenuse in this triangle is the AB side. AB = 2 x AM = 2 x 4 = 8 centimeters.
2. All sides of the rhombus are equal. Therefore, AB = AD = 8 centimeters. That is, the AED triangle is isosceles.
3. Calculate the degree measure ∠BAM:
∠BAM = 180 ° – (90 ° + 30 °) = 60 °.
4.∠АВD = ∠АDВ = (180 ° – 60 °) / 2 = 60 °.
All angles of triangle ABD are equal. Therefore, the indicated triangle is equilateral.
BD = AB = AD = 8 centimeters.
Answer: The length of the diagonal BD is 8 centimeters.