The height DK is drawn in parallelogram ABCD to side BC. The CDK angle is 22 degrees. Find the angle BAD.

Since DK is the height of the parallelogram, then the angle is DKC = 90. Then in a right-angled triangle СDK the angle is DСK = 180 – DKС – СDК = 180 – 90 – 22 = 68.

Since the opposite angles in the parallelogram are equal, the angle BAD = DCK = DCB = 68.

Answer: Angle BAD is 68.

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