The height drawn from the top of the obtuse corner of the rhombus divides its side into 5cm and 8cm long segments
The height drawn from the top of the obtuse corner of the rhombus divides its side into 5cm and 8cm long segments, counting from the top of the acute angle. Find the areas of the parts into which the rhombus divides this height.
Determine the length of the rhombus side. AB = BC = СD = AD = AН + DН = 5 + 8 = 13 cm.
From the right-angled triangle ABН, by the Pythagorean theorem, we determine the length of the leg BН.
BH ^ 2 = AB ^ 2 – AH ^ 2 = 13 ^ 2 – 5 ^ 2 = 169 – 25 = 144.
BH = 12 cm.
Determine the area of the rhombus.
Savsd = AD * ВН = 13 * 12 = 156 cm2.
Determine the area of the triangle ABН.
Savn = AН * ВН / 2 = 5 * 12/2 = 30 cm2.
Then the area of the ВНDС quadrangle will be equal to: Svnds = Savsd – Savn = 156 – 30 = 126 cm2.
Answer: The areas of the parts are 30 cm2 and 126 cm2.