The height drawn to the base of the isosceles triangle is 4 inches and the lateral side is 80 cm. Find the corners of the triangle.

Since the height in an isosceles triangle is perpendicular to the base, the sine of the angle a between the height and the side will be equal to:

sin (a) = 40: 80 = 1/2.

Therefore, the angle a is equal to: 30 degrees. Since the height is also a bisector, the apex angle is:

30 + 30 = 60.

Since in an isosceles triangle, the angles at the base are equal to each other:

(180 – 60) / 2 = 60.

Answer: all angles of a triangle are 60 degrees.