The height drawn to the base of the isosceles triangle is 4 inches, and the lateral side is 80 cm. Find the corners of the triangle.

Let’s designate the elements of the triangle. Let AC be the base, because the triangle is isosceles
AB = BC lateral sides HВ height.
1. In the HВ triangle is the height. Consider the triangle ABН, it is rectangular,
where AB is hypotenuse, ВН is leg. AB = 80 cm BH = 4 dm = 40 cm. BH is equal to half AB, which means the angle A = 30⁰ is the angle at the base, which means the angle C = 30, since the angles at the base of an isosceles triangle are equal.
2. Find angle B. The sum of the angles of the triangle is 180⁰.
B = 180 – (30 + 30) = 120⁰.
Answer: A = 30⁰; C = 30⁰; B = 120⁰.