The height drawn to the base of the isosceles triangle is 5.2 cm, and the side is 10.4 cm.

The height drawn to the base of the isosceles triangle is 5.2 cm, and the side is 10.4 cm. Find the angle opposite the base of the triangle.

Since the triangle ABC is isosceles, the angle ABC is equal to half the angle ABC.

Consider a triangle ABK, in which the angle K is straight, hypotenuse AB = 10.4 cm, leg BK = 5.2 cm.

Then Cos ABK = BK / AB = 5.2 / 10.4 = 1/2.

Cos ABK = 60.

Then Cos ABC = 60 * 2 = 120.

Answer: Cos ABC = 120.



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