The height of a regular quadrangular pyramid is 12 cm, and the side of the base is 24 cm.

The height of a regular quadrangular pyramid is 12 cm, and the side of the base is 24 cm. Calculate the dihedral angle at the base.

Since the pyramid is correct, then at its base there is a square, and the point of intersection of the diagonals O is the center of the square, then O1H = AD / 2 = 24/2 = 12 cm.

Consider a right-angled triangle OO1H, in which both legs are 12 cm, OO1 = O1H = 12 cm, then the triangle is rectangular and isosceles, and the angle at the base is OH = 450.

Answer: The dihedral angle ОНО1 is 450.



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