The height of a regular quadrangular pyramid is 18 dm, and the side of its base is 7√2 dm. Find the volume of a pyramid?

Since the pyramid is correct, there is a square at its base.

Then the area of the base of the pyramid will be equal to: Sbn = AB ^ 2 = (7 * √2) ^ 2 = 98 cm2.

Let’s define the volume of the pyramid.

Vpyr = Sbn * PO / 3 = 98 * 18/3 = 588 cm2.

Answer: The volume of the pyramid is 588 cm3.



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