Let’s call a right-angled triangle ABC. The height of a triangle is the perpendicular dropped from its vertex to the opposite side. Let us drop the perpendicular from point B to line AC. The AC line is divided into two parts – AH, HC. The height BH divides ABC into two right-angled triangles – ABH and HBC. Let the perimeter of ABH be p1 and HBC – p2. Knowing the perimeters of the two triangles, we can find the perimeter of ABC. To do this, you need to fold them.
p (ABC) = p1 + p2.
Answer: p (ABC) = p1 + p2.
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