The height of the BK is drawn in the triangle ABC. Prove that AB = BC and find the perimeter

The height of the BK is drawn in the triangle ABC. Prove that AB = BC and find the perimeter of the triangle ABC if BC = 31 cm, AK = CK = 28 cm.

Since AK = KC, the height BK is also the median, and therefore the triangle ABC is equilateral and AB = BC.

Then the perimeter of the triangle is:

P = 31 + 31 + 2 * 28 = 118 cm.

Answer: Ravs = 118 cm.



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