The height of the cone is equal to the radius R of its base. A plane is drawn through the apex of the cone, cutting
The height of the cone is equal to the radius R of its base. A plane is drawn through the apex of the cone, cutting off an arc of 60 degrees from the base circumference. Find S section
From the right-angled triangle AOB, by the Pythagorean theorem, we determine the length of the hypotenuse AB.
AB ^ 2 = OA ^ 2 + OB ^ 2 = 2 * R ^ 2.
AB = R * √2 cm.
Then ВK = BM = AB = R * √2 cm.
Since the chord KM cuts off an arc of 60, the triangle OKM is equilateral, OK = OM = KM = R cm.
The ВKM triangle is isosceles. Let’s build in it the height of the VN, which is also its median, then KН = KM / 2 = R / 2 cm.
Then, by the Pythagorean theorem, in the triangle ВKН, BH ^ 2 = BK ^ 2 – KH ^ 2 = 2 * R ^ 2 – R ^ 2/4 = 7 * R ^ 2/4.
BH = √7 * R / 2 cm.
Determine the cross-sectional area.
Ssection = KM * ВН / 2 = R * (√7 * R / 2) / 2 = R^2 * √7 / 4 cm2.
Answer: The cross-sectional area is R^2 * √7 / 4 cm2.