The height of the cylinder is 6 cm, the area of its axial section is 60 cm2, calculate the circumference of the base of this cylinder.

The axial section of the cylinder is a rectangle AВСD, two sides of which are the height of the cylinder, the other two are the diameter of the base, then:
Savsd = AB * BC = 60 cm2.
BC = 60 / AB = 60/6 = 10 cm.
BC is the diameter of the circle, then OB = R = BC / 2 = 10/2 = 5 cm.
Determine the length of the circle.
L = 2 * n * R = 2 * n * 5 = 10 * n cm.
Answer: The circumference is 10 * n cm.



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