The height of the cylinder is 8 cm, and the diagonals of its axial section are mutually perpendicular.

The height of the cylinder is 8 cm, and the diagonals of its axial section are mutually perpendicular. Find the radius of the base of the cylinder.

The axial section of a straight cylinder is a rectangle with two opposite sides having the diameters of the circles, and the other two are generators.

Since, by condition, the diagonals of the axial section are perpendicular, a rectangle with perpendicular diagonals is a square. Then AB = BC = CD = AD = D = 8 cm.

ОА = R = АD / 2 = 8/2 = 4 cm.

Answer: The radius of the base of the cylinder is 4 cm.



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