The height of the isosceles trapezoid drawn from the vertex C divides the base AD

The height of the isosceles trapezoid drawn from the vertex C divides the base AD into segments of length 11 and 14. Find the length of the base BC.

According to the condition, an isosceles trapezoid is given, which means that the heights drawn from the vertices B and C divide the trapezoid into a rectangle and two equal right-angled triangles. Since the height drawn from vertex C divides the base AD into segments of length 11 and 14, the smaller segment is the leg of one triangle, which means the leg of the second triangle is also 11. Then the remaining segment 14 consists of a segment equal to the smaller base of BC and the leg of the second triangle.
So, 14 – 11 = 3 – the length of the BC base.



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