The height of the isosceles trapezoid drawn from the vertex C divides the base AD

The height of the isosceles trapezoid drawn from the vertex C divides the base AD into segments of length 10 and 11 find the length of the base BC.

Let the height CH be the height from the top of C. DH = 10 (by condition) and AH = 11 (by condition). Let’s draw one more height BE from the top B.

Triangles ABE and DCH are equal (isosceles trapezoid).

Hence, AE = DH = 10.

This means that the segment EH = AH – AE = 11 – 10 = 1.

ВС = ЕН (ВEНС  is a rectangle between two heights).

Answer: BC = 1.



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