The height of the isosceles triangle, drawn to the base, is 5cm, and the base is 24cm. Find the side 2.

Given:

BH = 5 cm;
AC = 24 cm;
AB = BC =?
The height BH drawn to the base coincides with the median:

AH = CH = 1/2 * AC = 1/2 * 24 = 12 (cm).

Triangle ABH – rectangular:

AB = √ (AH² + BH²) = √ (12² + 5²) = √ (144 + 25) = √169 = 13 (cm).



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